Can anyone take the first and second derivative of this: y=3(x^2/3) - (x^2)
J joey123 New member Joined Oct 23, 2005 Messages 29 Nov 6, 2005 #1 Can anyone take the first and second derivative of this: y=3(x^2/3) - (x^2)
W warsatan New member Joined Sep 12, 2005 Messages 36 Nov 6, 2005 #2 1st deriv. 2x^(-1/3) -2x 2nd deriv. (-2/3)x^(-4/3) -2
G Guest Guest Nov 6, 2005 #4 y=3(x^2/3) - (x^2) y' = 3 (2/3) (x^(-1/3)) - 2 x y' = 6/3 (x^(-1/3) - 2x y'' = (6/3)(-1/3) (x^(-4/3)) - 2 y'' = (-6/9) (x^(-4/3)) - 2 y'' = (-2/3) (x^(-4/3)) - 2
y=3(x^2/3) - (x^2) y' = 3 (2/3) (x^(-1/3)) - 2 x y' = 6/3 (x^(-1/3) - 2x y'' = (6/3)(-1/3) (x^(-4/3)) - 2 y'' = (-6/9) (x^(-4/3)) - 2 y'' = (-2/3) (x^(-4/3)) - 2
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Nov 6, 2005 #5 Please also review the other threads, here and here, that you started on this same problem. And please stop multi-posting. Thank you. Eliz.
Please also review the other threads, here and here, that you started on this same problem. And please stop multi-posting. Thank you. Eliz.