A, b and c working together completed a job in 10 days. However, c only worked for the first three days when 37/100 of the job was done. Also, the work done by a in 5 days is equal to the work done by b in 4 days. How many days would be required by the fastest worker to complete the entire work?
Wa per day * 5days = Wb per day * 7 days
(Wa + Wb + Wc ) * 3 days = 37/ 100
(Wa + Wb ) * 7 days =1 - 37/100
=> Wa * 5 days + Wb * 4 days + Wa *2 days + Wb * 3 days = 63/100
=> Wa * 5 days + Wa * 5 days + Wa *2 days + Wb * 3 days = 63/100
=> 12 Wa + 3Wb = 63/100
Work by A in 5 days = x
per day Work by A = x/5
Work by B in 4 days = x
per day Work by B = x/4
Work by A in 3 days = 3x / 5
Work by B in 3 days = 3x / 4
3x / 5 + 3x / 4 + ( Work per day by C * 3 days )= 37/ 100 . another equation
Wa per day * 5days = Wb per day * 7 days
(Wa + Wb + Wc ) * 3 days = 37/ 100
(Wa + Wb ) * 7 days =1 - 37/100
=> Wa * 5 days + Wb * 4 days + Wa *2 days + Wb * 3 days = 63/100
=> Wa * 5 days + Wa * 5 days + Wa *2 days + Wb * 3 days = 63/100
=> 12 Wa + 3Wb = 63/100
Work by A in 5 days = x
per day Work by A = x/5
Work by B in 4 days = x
per day Work by B = x/4
Work by A in 3 days = 3x / 5
Work by B in 3 days = 3x / 4
3x / 5 + 3x / 4 + ( Work per day by C * 3 days )= 37/ 100 . another equation