Three diggers dug a ditch of 324 m deep in six days working simultaneously. During one shift, the third digger digs as many metres more than the second as the second digs more than the first. The third digger's work in 10 days is equal to the first digger's work in 14 days. How many metres does the first digger dig per shift?
Work done per day by c ,b ,a = Wc , Wb , Wa
Wc= Wa * 5/7
( Wb + Wa + Wc) * 6 = 324
Wa + Wb + Wc = 54 m per day work combined
ONE shift work
Work of that shift by b= Wb1 , by C = Wc1
Wb1 = (Wa + x) metres ,
Wc1 = ( Wb1 + x ) metres
Work done per day by c ,b ,a = Wc , Wb , Wa
Wc= Wa * 5/7
( Wb + Wa + Wc) * 6 = 324
Wa + Wb + Wc = 54 m per day work combined
ONE shift work
Work of that shift by b= Wb1 , by C = Wc1
Wb1 = (Wa + x) metres ,
Wc1 = ( Wb1 + x ) metres