t=43dx/dt + 836 (dx/dt)^2

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gwin

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Oct 31, 2008
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I'm trying to solve the ode:
t=43dx/dt + 836 (dx/dt)^2
It's to find the level of water above a packed bed filter.
I'm ok with linear odes but am really unsure about what to do with this one. Is there a way of getting a numerical solution?

Thanks
Glen
 
gwin said:
I'm trying to solve the ode:
t=43dx/dt + 836 (dx/dt)^2
It's to find the level of water above a packed bed filter.
I'm ok with linear odes but am really unsure about what to do with this one. Is there a way of getting a numerical solution?

Thanks
Glen
Click to expand...

Are you looking for "numerical solution" (x= number at a given t - approximate solution usually found through iterative process using computer) or closed-form solution [ x = f(t)]?

For numerical solution, convert your DE into "difference equations" over the given domain and solve it using suitable methods (that is whole another branch of mathematics).
 
I don't need an exact solution, but it would be good.
I think I'll be able to find an approximation using steps.

Thanks
 
Sorry ODE is x=43dx/dt+836(dx/dt)^2

Sorry,

I wrote the equation wrong before. The equation I want to solve is:

x=43dx/dt+836(dx/dt)^2

Thanks
Glen
 
Re: Sorry ODE is x=43dx/dt+836(dx/dt)^2

gwin said:
Sorry,

I wrote the equation wrong before. The equation I want to solve is:

x=43dx/dt+836(dx/dt)^2

Thanks
Glen
Click to expand...

Same advice....

Please share with us your work - indicating exactly where you are stuck - so that we know where to begin to help you.
 
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