I need to set to K= T= 2pi times the square root of (k/m)
S swetpear087 New member Joined Dec 2, 2008 Messages 3 Dec 2, 2008 #1 I need to set to K= T= 2pi times the square root of (k/m)
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Dec 2, 2008 #2 Re: easy help please Hello, swetpear087! \(\displaystyle \text{Solve for }k\!:\;\;T\;= \;2\pi\sqrt{\frac{k}{m}}\) Click to expand... \(\displaystyle \text{We have: }\;2\pi\sqrt{\frac{k}{m}} \;=\;T\) \(\displaystyle \text{Divide by }2\pi\!:\quad \sqrt{\frac{k}{m}} \;=\;\frac{T}{2\pi}\) \(\displaystyle \text{Square both sides: }\;\left(\sqrt{\frac{k}{m}}\right)^2 \;=\;\left(\frac{T}{2\pi}\right)^2 \quad\Rightarrow\quad \frac{k}{m} \;=\;\frac{T^2}{4\pi^2}\) \(\displaystyle \text{Multiply by }m\!:\quad k \;=\;\frac{mT^2}{4\pi^2}\)
Re: easy help please Hello, swetpear087! \(\displaystyle \text{Solve for }k\!:\;\;T\;= \;2\pi\sqrt{\frac{k}{m}}\) Click to expand... \(\displaystyle \text{We have: }\;2\pi\sqrt{\frac{k}{m}} \;=\;T\) \(\displaystyle \text{Divide by }2\pi\!:\quad \sqrt{\frac{k}{m}} \;=\;\frac{T}{2\pi}\) \(\displaystyle \text{Square both sides: }\;\left(\sqrt{\frac{k}{m}}\right)^2 \;=\;\left(\frac{T}{2\pi}\right)^2 \quad\Rightarrow\quad \frac{k}{m} \;=\;\frac{T^2}{4\pi^2}\) \(\displaystyle \text{Multiply by }m\!:\quad k \;=\;\frac{mT^2}{4\pi^2}\)