Systems of equations & equalities

barto

New member
Joined
Sep 9, 2006
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5
5 x + 2y =4
3x + 4y + 2z =6
7x + 3y + 4z =29

I've worked it, and worked it, and whenever I check my answer, it never fits with the problem.

I had x = 1.56
y = -207/109
z = 4.46

This is driving me crazy. Thaks for your help.
 
barto said:
I've worked it, and worked it, and....
What method are you using? What were your steps?

Thank you.

Eliz.
 
barto said:
I'm using process of elimination. Do you know how to do this?
Yeah.... But I try to avoid it for systems with more than two variables though; it can get awfully messy.... :shock:

There isn't just one "right" way, of course. One set of steps might be as follows:

1) Multiply the second row by "2". Subtract this from the third row. The first and third rows now have only x and y.

2) Solve this subsystem: Multiply the third row by "5", and subtract the third row from the first. Solve the result for y. Back-solve for x.

3) Plug the values of x and y into either of the second or third (original) rows, and solve for z.

Eliz.
 
Thanks, Eliz...I'll try it now! It's my last problem of the night and it's got to work.
 
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