SovereignPariah
New member
- Joined
- Nov 14, 2013
- Messages
- 1
A canoeist travels 20 miles down a river and back in 8 hours (40 mile round trip). She can paddle 5 miles down the rive in the same time that she can paddle 3 miles up the river. Find her rate in still water and the rate of current.
Now, the problem I have is that I seem to be missing a variable to solve the question.
time = rate X distance
b = rate in still water
c = rate of current
Downstream: is 20 = (b+c)t1
Upstream: is 20 = (b-c)t2
20/(b+c) + 20/(b-c) = 8
t1 + t2 = 8
3/(b-c) = 5 /(b+c)
Above is what I think I know about the question. I can't seem to bring it together to find the answers. I know the answer from the back of the book is b = 5.3 and c = 1.3 but I don't know how they got it. I'm probably thinking too hard. Help please.
Now, the problem I have is that I seem to be missing a variable to solve the question.
time = rate X distance
b = rate in still water
c = rate of current
Downstream: is 20 = (b+c)t1
Upstream: is 20 = (b-c)t2
20/(b+c) + 20/(b-c) = 8
t1 + t2 = 8
3/(b-c) = 5 /(b+c)
Above is what I think I know about the question. I can't seem to bring it together to find the answers. I know the answer from the back of the book is b = 5.3 and c = 1.3 but I don't know how they got it. I'm probably thinking too hard. Help please.