System of Equations percentage question

[monochrom]

Hello all, I'm new to this forum, nice to meet you all.
My problem is I have no idea where to go from this problem or if im setting it up wrong

Here is a screenshot,


I apologize for the small font, I am unable to maximize it , i hope you are able to read it. If not, i will rewrite the problem down below,

Question:
A chemist needs 2 liters of a 12% acid solution. He has a 10% solution available to form the mixture. How much of each should be used to form the 12% solution?
The chemist needs to mix [insert answer] liters of 10% solution with [insert answer] liters of 20% solution to make 2 liters of a 12% acid solution (simplify your answers)

So I have a couple notes on how to set up the overall problem.
first i would make two equations one equation would be x+y=2 and 0.10x+0.20y=0.24 I think.

Im just really confused I dont know where to begin.

Respond as soon as you can thank you.

 

[ksdhart2]

Well, the first thing I'd do is explicitly declare your variables. You don't state anywhere what x and y stand for. From context, I'll assume that x represents the number of litres of the 10% solution used, and y represents the number of litres of the 20% solution used. Assuming these are the correct meanings, then I agree with your first equation. The second is close, but not quite right. Given that the chemist's goal is to create a 12% solution, where did the 0.24 come from? Once that small error is corrected, you're good to go - just solve that system of equations using your preferred method. Or, are you perhaps also needing hints as to how to solve the system?

 

[stapel]

My problem is I have no idea where to go from this problem or if im setting it up wrong

Question:
A chemist needs 2 liters of a 12% acid solution. He has a 10% solution available to form the mixture. How much of each should be used to form the 12% solution?

...I'm just really confused I dont know where to begin.

To learn how to set up and solve "mixture" word problems, try here.