mathmarauder
Junior Member
- Joined
- Oct 25, 2008
- Messages
- 68
I have been asked to find all the zeros of f(x)
2x^3 + x^2 - 13x + 6
fundamental theorem of algebra tell me I have 3 zeros
2 possible positive zeros
1 possible negative zero
rational zero test (+- = plus and negative)
+-1, +-2, +-3, +-6, +-1/2, +-2/2,+-3/2,+-6/2
now the final step...synthetic division,
I know if the remainder is zero, the number we plugged in to get that
0 is the answer or one of the answers... any help please?
Ok i did the synthetic division and it seems like 2 is the only zero
find all zeroes of f(x) = 2 is this correct?
2x^3 + x^2 - 13x + 6
fundamental theorem of algebra tell me I have 3 zeros
2 possible positive zeros
1 possible negative zero
rational zero test (+- = plus and negative)
+-1, +-2, +-3, +-6, +-1/2, +-2/2,+-3/2,+-6/2
now the final step...synthetic division,
I know if the remainder is zero, the number we plugged in to get that
0 is the answer or one of the answers... any help please?
Ok i did the synthetic division and it seems like 2 is the only zero
find all zeroes of f(x) = 2 is this correct?