Symmetric group

[Kurchi]

In S_n , order of every element is a divisor of n! . But, is every divisor of n! a possible order for elements of S_n ?

 

[Steven G]

Yes, of course every divisor of n! is a possible order for elements of S_n.

Are you sure that you meant to write what you wrote? Did you meant to ask if every divisor of n! has an element of that order?