Suppose that the h is described for all real numbers as it follows

[Khankhan]

H(x) = -1/2x +1 if x < -2
H(x) = -(x+1) two as an exponent +3 if -2 is less than or equal to x is less than or equal to 1
H(x) = 4 if x > 1

H(-3)=
H(-2)=
H(-1)=

 

[pka]

H(x) = -1/2x +1 if x < -2
H(x) = -(x+1) two as an exponent +3 if -2 is less than or equal to x is less than or equal to 1
H(x) = 4 if x > 1

H(-3)=
H(-2)=
H(-1)=

\(\displaystyle H(x) = \left\{ {\begin{array}{*{20}rc}{\dfrac{{ - 1}}{{2x + 4}},}&{x < - 2}\\{ - {{\left( {x + 1} \right)}^2} + 3,}&{ - 2 \le x \le 1}\\{4,}&{1 < x}\end{array}} \right.\)

Do you plan to show sum effort?

 

[Quaid]

-1/2x + 1

Hello Khan,

Is that first part \(\displaystyle -\dfrac{1}{2}x + 1\)

or \(\displaystyle \dfrac{-1}{2x + 1}\)

?

 

[lookagain]

Hello Khan,

Is that first part \(\displaystyle -\dfrac{1}{2}x + 1\)

or \(\displaystyle \dfrac{-1}{2x + 1}\)

?

Or is it \(\displaystyle \ \dfrac{-1}{2x} \ + \ 1 \ ?\)

 

[mmm4444bot]

Or is it \(\displaystyle \ \dfrac{-1}{2x} \ + \ 1 \ ?\)

Also a good question, lookagain.

@KhanKhan: please take time to read the forum guidelines. Here's a link to the summary page.

(You'll find links to the complete rules and guidelines appear near the bottom.)

Thank you! :cool: