Suppose angles 1 and 2 are vertical. What is the value of...

Cinnamon

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Suppose Angle 1 and 2 are vertical angles. What is the value of Y if M of angle 1 equals y + 82 and M of 2 equals 6Y-8. What are the measures of 1 angles 1 and 2
 
That makes no sense... Is that the whole problem? Were there any pictures included?
 
re-written

Suppose <1 and <2 are vertical angles. What is the value of y if m(<1) = y + 82 and m(<2) = 6y - 8? What are the measures of <1 and <2?

Note: "m(<1)" means "the measure of angle 1".
 
Re: OKAY THEN

Hello, Cinnamon!

Do you know anything about vertical angles?

Suppose 1\displaystyle \angle 1 and 2\displaystyle \angle 2 are vertical angles.

What is the value of y\displaystyle y if m1=y+82\displaystyle m\angle 1\:=\:y\,+\,82 and m2=6y8\displaystyle m\angle2\:=\:6y\,-\,8 ?

What are the measures of 1\displaystyle \angle1 and 2\displaystyle \angle 2 ?
Code:
      *           *
       \         /
        \       /
         \     /
          \   /
           \ /
    y+82 (1 * 2) 6y-8
           / \
          /   \
         /     \
        /       \
       /         \
      *           *
You're expected to know that vertical angles are equal: 1=2\displaystyle \,\angle1\,=\,\angle2

So we have: y+82  =  6y8\displaystyle \,y\,+\,82\;=\;6y\,-\,8

So can solve for y\displaystyle y, then determine the sizes of 1\displaystyle \angle1 and 2\displaystyle \angle 2
 
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