If [imath]a + \dfrac{1}{a} = 4[/imath], then what is a?Hellow, I need help in solving this expression :
View attachment 36683
I tried converting to quadratic or quartic equation, but can't proceed any further.
View attachment 36684
thank you for help
sorry? a is a variable right?If [imath]a + \dfrac{1}{a} = 4[/imath], then what is a?
-Dan
I gave you a big hint. And, yes, a is a variable.sorry? a is a variable right?
Hellow, I need help in solving this expression :
View attachment 36683
I tried converting to quadratic or quartic equation, but can't proceed any further.
thank you for help
Hellow, I need help in solving this expression :
View attachment 36683
I tried converting to quadratic or quartic equation, but can't proceed any further.
View attachment 36684
thank you for help
First a^2 + 1/a^2 is not 16.oh after doing some algebra ---> a^2 + 1/a^2 = 16
I multiply all by 4 which gives 56
so subtract that from 256
Thank you Mr Steven!
I'm not saying arriving at a^2 + 1/a^2 = 14 is wrong but I wonder after arriving at what you got on post 10, how did you get a^2 + 1/a^2 = 14??Ah I made some careless typo & calculations, I edited my #12 hopefully that works
250-56 =194
I followed up on Dr Peterson advice to do some manipulation in the middle, from squaring the equation into quadraticI'm not saying arriving at a^2 + 1/a^2 = 14 is wrong but I wonder after arriving at what you got on post 10, how did you get a^2 + 1/a^2 = 14??
Thena^2 + 1/a^2 = 14
You already had in your prior post that (a^2 + 2+ 1/a^2) = 16^2. That means that a^2 + 2+ 1/a^2 =1 6. From there a^2 +1/a^2 = 14 (14 + 2 = 16).I followed up on Dr Peterson advice to do some manipulation in the middle, from squaring the equation into quadratic