supplemental algebra II homework

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joebob

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Sep 23, 2008
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in my honors algebra 2 class my teacher gives us super hard supplent homeowrk and i have no idea how to do it
1. a line passes through the points (-1,5) and (3,k) and has a y- of 7. find the value of k
2. the boundary line is parallel to the line -6x + 3y = 11 an passes through the point (1,5), which is not a solution. the point (10,3) is not a solution of the inequality

this is exacly how they were writen
can anyone please help
 
joebob said:
... this is exacly how they were writen ...
Click to expand...

Hello Joe Bob:

I doubt it. :!:

In light of the spelling, grammatical errors, and the missing mathematical information, I'd say that you're probably sloppy, instead. (Out of fairness to you, I note that you never stated enrollment in honors English ...)

Exercise 2 does not even ask a question!

In exercise 1, I have to guess what the phrase "a y- of 7" is supposed to mean.

I'll guess that your teacher told you that the y-intercept of this line is the point (0, 7).

So you've been given two points on a line. These points are (-1, 5) and (0, 7).

Do you know how to write the equation for this line?

Once you have an equation, then all you need to do is substitute 3 for x to find the corresponding y value. This value is the same as the value for k, since k is the y-coordinate of the point (3, k).

If you could manage to find the question for exercise 2, then I would probably be able to help you with that exercise, as well.

Cheers,

~ Mark :)

PS: Show your work!
 
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