Super complicated equation solve for x: 0=(x^(z*y)-((z^(z^y)+(z^z+y)^z)*z^(y^z+z)+...

[TheAnomaly]

My friend sent this to me. Is there a pattern or is it completely random? Solve for x

0=(x^(z*y)-((z^(z^y)+(z^z+y)^z)*z^(y^z+z)+(z^z+y)*(y^z+z))*x^(z^z)+(z^z*y^(z^z)*((z^z+y)^z-z)*(y^(z^z)-z)*(z^z*z+y)))*x^z)^z-(z^(z^z+y)*y^(z^y)*(z+y)^z*(z^z+y)^z*((z+y)^z-z)^z*(z^(z+y)+(z+y))^z)*(x^(z*y)-((z^(z^y)+(z^z+y)^z)*(y^z+z)*x^(z^z)+(z^z*y^(z^z)*((z^z+y)^z-z)*(y^(z^z)-z)*(z^z*y^y*(z+y)^(z^z)-(z^z+y)))*x^z)+(z^(z^z*y)*y^(z^(z^z))*(z^z)*((z+y)^z-z)^(z^z)*(z^(z+y)+(z+y))^(z^z))=

z-y+z-y+z=

z^z^y-y^(z+y)-y^z-z^z

Thanks!

 

[mmm4444bot]

My friend sent this to me. Is there a pattern or is it completely random? Solve for x

0=(x^(z*y)-((z^(z^y)+(z^z+y)^z)*z^(y^z+z)+(z^z+y)*(y^z+z))*x^(z^z)+(z^z*y^(z^z)*((z^z+y)^z-z)*(y^(z^z)-z)*(z^z*z+y)))*x^z)^z-(z^(z^z+y)*y^(z^y)*(z+y)^z*(z^z+y)^z*((z+y)^z-z)^z*(z^(z+y)+(z+y))^z)*(x^(z*y)-((z^(z^y)+(z^z+y)^z)*(y^z+z)*x^(z^z)+(z^z*y^(z^z)*((z^z+y)^z-z)*(y^(z^z)-z)*(z^z*y^y*(z+y)^(z^z)-(z^z+y)))*x^z)+(z^(z^z*y)*y^(z^(z^z))*(z^z)*((z+y)^z-z)^(z^z)*(z^(z+y)+(z+y))^(z^z))=

z-y+z-y+z=

z^z^y-y^(z+y)-y^z-z^z

Thanks!

An equation contains one equals sign; your post contains three equals signs. What is the left-hand side of the equation? What is the right-hand side of the equation?

Also, I copied-and-pasted the expression between your first two equals signs into a computer algebra system, and the software is telling me that the parentheses are mismatched. Please check your typing; I have highlighted in red above the position of the unexpected parenthesis.

 

[Harry_the_cat]

My friend sent this to me.

You need to get a new friend!