Sum of Rational and Irrational

harpazo

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Jan 31, 2013
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I asked my friend the following question:

Why is the sum of a rational number and irrational number irrational?

Here is his reply.

Let's assume that the sum of the rational number a/b (where a and b are integers) and irrational number x is also a rational number c/d (where c and d are some integer), i.e.

(a/b) + x = c/d

Then x = (c/d) - (a/b)

RHS is clearly rational while LHS is irrational. This is a contradiction.

So, the sum must be irrational.

Question:

Does this reply make sense?
 
Yes, that is a pretty standard "proof by contradiction". To prove "if P then Q", assume Q is false and that this leads to a contradiction. Here the conclusion is "the sum is irrational". We assume it is a rational number and use the properties of rational numbers (that they are closed under subtraction) to arrive that the result that a number is also rational contradicting the hypothesis that it is irrational.
 
I asked my friend the following question:

Why is the sum of a rational number and irrational number irrational?

Here is his reply.

Let's assume that the sum of the rational number a/b (where a and b are integers) and irrational number x is also a rational number c/d (where c and d are some integer), i.e.

(a/b) + x = c/d

Then x = (c/d) - (a/b)

RHS is clearly rational while LHS is irrational. This is a contradiction.

So, the sum must be irrational.

Question:

Does this reply make sense?
Yes.... This type of logic (argument) is called "reductio ad absurdum".
 
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