Repeated sum of digits of 9*k = 9 → Repeated sum of digits of 9*k + 1= 10 → Repeated sum of digits of 9*k + 1= 1If k∈Z+∧9k+1, prove that
the reapiting sum digits of 9k+1 equals at the end 1
For example if:
k=1 then 9∗1+1=10→1+0=1
k=2 then 9∗2+1=19→1+9=10→1+0=1
k=15 then 9∗15+1=136→1+3+6=10→1+0=1
Always it ends to 1. Why?
Repeated sum of digits of 9*k = 9 → Repeated sum of digits of 9*k + 1= 10 → Repeated sum of digits of 9*k + 1= 1
(that is a method of calculating "divisibility" by 9)
The basic idea is that when you add the digits of a number, the result differs from the number itself by a multiple of 9. This is because, for example, a 5 in the hundreds place of the number represents 5*100, while in the digit sum it is just 5; the difference between these is 5*(100-1) = 5*99 which is a multiple of 9. The same sort of thing happens with any digit in any place.If k∈Z+∧9k+1, prove that
the reapiting sum digits of 9k+1 equals at the end 1
For example if:
k=1 then 9∗1+1=10→1+0=1
k=2 then 9∗2+1=19→1+9=10→1+0=1
k=15 then 9∗15+1=136→1+3+6=10→1+0=1
Always it ends to 1. Why?
Of course it isn't true! You found a counterexample!So this thought: Repeated sum of digits of 9*k + 1= 10 Is it still true?
See if you can turn my argument into the kind you want! I find people grasp the idea more quickly from an example, so that's what I start with; symbolic explanations tend to get bogged down in details. But since you're happier with symbols, give it a try. That's a better way to learn than having it handed to you.I would prefer to see a strictly analytic algebraic solution in order to understand it clearly.
That doesn't surprise me, since you said "algebraic", not "number theory".I am not gonna lie, but I am not familiar with modular. I never used consciously modular and I never tried to solve exercises with modular before. But I can understand, what the symbols means. So if you prove it I will be happy.
Thank you, Thank you, Thank you, Thank you... Very much for your time and help Thank you!That doesn't surprise me, since you said "algebraic", not "number theory".
For an algebraic explanation, see https://en.wikipedia.org/wiki/Casting_out_nines
For number theoretic details, see the link there to digital root.
And if you are not familiar with casting out nines, a search for that term will bring you lots of information.