ChaoticLlama
Junior Member
- Joined
- Dec 11, 2004
- Messages
- 199
I don't know what method I should use to evaulate this infinite series.
With basic algebra that series is equal to: \(\displaystyle \L\ 2\sum\limits_{n = 1}^\infty {\left( {\frac{2}{3}} \right)} ^n\)
Any help would be appreciated.
What is the value of \(\displaystyle \L\sum\limits_{n = 1}^\infty {\frac{{2^{n + 1} }}{{3^n }}}\)
With basic algebra that series is equal to: \(\displaystyle \L\ 2\sum\limits_{n = 1}^\infty {\left( {\frac{2}{3}} \right)} ^n\)
Any help would be appreciated.