(3y-5) - (4y-2) (2y-6) (5y-15) please help im so confused?
M mcg37 New member Joined Mar 25, 2010 Messages 1 Mar 25, 2010 #1 (3y-5) - (4y-2) (2y-6) (5y-15) please help im so confused?
M masters Full Member Joined Mar 30, 2007 Messages 378 Mar 25, 2010 #2 mcg37 said: (3y-5) - (4y-2) (2y-6) (5y-15) please help im so confused? Click to expand... Hi mcg37, \(\displaystyle \frac{3y-5}{2y-6}-\frac{4y-2}{5y-15}\) We need to find a common denominator, so let's simplify a little bit and see what happens. \(\displaystyle \frac{3y-5}{2(y-3)}-\frac{4y-2}{5(y-3)}\) Looks like the LCD = \(\displaystyle 10(y-3)\) Now, we'll convert each fraction to the new denominator. [1] \(\displaystyle \frac{3y-5}{2(y-3)} \cdot \frac{5}{5}=\frac{5(3y-5)}{10(y-3)}\) [2] \(\displaystyle \frac{4y-2}{5(y-3)}\cdot \frac{2}{2}=\frac{2(4y-2)}{10(y-3)}\) Now, subtract [1] - [2] \(\displaystyle \frac{5(3y-5)}{10(y-3)}-\frac{2(4y-2)}{10(y-3)}=\frac{5(3y-5)-2(4y-2)}{10(y-3)}=\) Now, try and finish up.
mcg37 said: (3y-5) - (4y-2) (2y-6) (5y-15) please help im so confused? Click to expand... Hi mcg37, \(\displaystyle \frac{3y-5}{2y-6}-\frac{4y-2}{5y-15}\) We need to find a common denominator, so let's simplify a little bit and see what happens. \(\displaystyle \frac{3y-5}{2(y-3)}-\frac{4y-2}{5(y-3)}\) Looks like the LCD = \(\displaystyle 10(y-3)\) Now, we'll convert each fraction to the new denominator. [1] \(\displaystyle \frac{3y-5}{2(y-3)} \cdot \frac{5}{5}=\frac{5(3y-5)}{10(y-3)}\) [2] \(\displaystyle \frac{4y-2}{5(y-3)}\cdot \frac{2}{2}=\frac{2(4y-2)}{10(y-3)}\) Now, subtract [1] - [2] \(\displaystyle \frac{5(3y-5)}{10(y-3)}-\frac{2(4y-2)}{10(y-3)}=\frac{5(3y-5)-2(4y-2)}{10(y-3)}=\) Now, try and finish up.
