subnets and hosts

[logistic_guy]

The network address of \(\displaystyle 172.16.0.0/19\) provides how many subnets and hosts?

\(\displaystyle \bold{A.}\) 7 subnets, 30 hosts each
\(\displaystyle \bold{B.}\) 7 subnets, 2,046 hosts each
\(\displaystyle \bold{C.}\) 7 subnets, 8,190 hosts each
\(\displaystyle \bold{D.}\) 8 subnets, 30 hosts each
\(\displaystyle \bold{E.}\) 8 subnets, 2,046 hosts each
\(\displaystyle \bold{F.}\) 8 subnets, 8,190 hosts each

 

[khansaheb]

The network address of \(\displaystyle 172.16.0.0/19\) provides how many subnets and hosts?

\(\displaystyle \bold{A.}\) 7 subnets, 30 hosts each
\(\displaystyle \bold{B.}\) 7 subnets, 2,046 hosts each
\(\displaystyle \bold{C.}\) 7 subnets, 8,190 hosts each
\(\displaystyle \bold{D.}\) 8 subnets, 30 hosts each
\(\displaystyle \bold{E.}\) 8 subnets, 2,046 hosts each
\(\displaystyle \bold{F.}\) 8 subnets, 8,190 hosts each

Please show us what you have tried and exactly where you are stuck.

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Please share your work/thoughts about this problem

 

[logistic_guy]

Let us first write down the subnet mask.

\(\displaystyle /19\) gives:

subnet mask \(\displaystyle = 11111111.11111111.11100000.00000000 = 255.255.224.0\)

Once we have the subnet mask in hand, everything else can be solved easily. And that's what we'll do in the next post.

Piece of Cake

 

[logistic_guy]

This formula \(\displaystyle 2^x\) gives us the number of subnets,

where \(\displaystyle x\) is the number of \(\displaystyle 1s\) in the interesting octet

Then, the number of subnets is:

\(\displaystyle 2^3 = 8 \ \text{subnets}\)

 

[logistic_guy]

This formula \(\displaystyle 2^y - 2\) gives the number of hosts per subnet,

where \(\displaystyle y\) is the number of all available \(\displaystyle 0s\).

Then, the number of hosts is:

\(\displaystyle 2^{13} - 2 = 8190\)

And the answer is:

\(\displaystyle \bold{F.}\) 8 subnets, 8,190 hosts each