Stumped

[Misty]

Find the measures of the angles of a triangle if the measure of one angle is 10degrees more than twice the measure of the second angle and the third angle measures thirty degrees less than twice the second angle? :roll:

 

[Mrspi]

Find the measures of the angles of a triangle if the measure of one angle is 10degrees more than twice the measure of the second angle and the third angle measures thirty degrees less than twice the second angle? :roll:

Since the measures of both the first and third angle are given in terms of the second angle, it seems to make sense to define a variable to represent the measure of the second angle.

Let x = measure of the second angle of the triangle

Then, the first angle is 10 degrees more than twice the measure of the second angle. So,
2x + 10 = measure of the first angle of the triangle

Use similar reasoning to define the measure of the third angle of the triangle.

Then, remember that the sum of the angles of any triangle is 180 degrees.

first angle + second angle + third angle = 180.................this will be the basis of an equation.

Once you've found the value of x, you should be able to find the measures of the other two angles.