Stuck

nz.lauren

New member
Joined
Jun 23, 2012
Messages
6
Hi,

I have (1 + 0.12 / 2)^2 = (1 + r/12)^12, solve for r. r should equal 0.117106, but I can't get to this result.

I'm trying to solve like this:

0.1236 = (1 + r/12)^12

0.1236^(1/12) = 1 + r/12

0.840107521 = 1 + r/12

12 * 0.840107521 = 1+ r

r = 9.0812902

Clearly I'm doing something stupid but I don't know what. Is it a problem with my order of operations? I've tried other orders but can't make it work.

Thanks!
 
Hi,

I have (1 + 0.12 / 2)^2 = (1 + r/12)^12, solve for r. r should equal 0.117106, but I can't get to this result.

I'm trying to solve like this:

0.1236 = (1 + r/12)^12 See [1] below

0.1236^(1/12) = 1 + r/12

0.840107521 = 1 + r/12

12 * 0.840107521 = 1+ r See [2] below

r = 9.0812902

Clearly I'm doing something stupid but I don't know what. Is it a problem with my order of operations? I've tried other orders but can't make it work.

Thanks!

[1]: [1 + (.12/2)]² = 1.1236 NOT 0.1236

[2]: When you multiply everything by 12 make sure you multiply EVERYTHING by 12, including the 1 in the 1 + r/12 term.
 
Hi,

I have (1 + 0.12 / 2)^2 = (1 + r/12)^12, solve for r. r should equal 0.117106, but I can't get to this result.

I'm trying to solve like this:

0.1236 = (1 + r/12)^12
Personally, I would have started by taking the square root of both sides: (1+ 0.06)= (1+ r/12)^6.

Now, take the sixth root of both sides \(\displaystyle \sqrt[6]{1.06}= 1.0098= 1+ r/12\) so that r/12= .0098 and r= 12(.0098)= .1171

0.1236^(1/12) = 1 + r/12

0.840107521 = 1 + r/12

12 * 0.840107521 = 1+ r
Unless you meant (1+ r)/12, this is wrong. with .840107521= 1+ (r/12), multiplying both sides by 12 gives 12*.840107521= (1+ r/12)(12)= 12+ r/12.

r = 9.0812902

Clearly I'm doing something stupid but I don't know what. Is it a problem with my order of operations? I've tried other orders but can't make it work.

Thanks!
 
Thanks guys. It's always upsetting to come back the next day and realise you were doing something truly stupid (like forgetting to add the 1 in (1 + 0.12/ 2)^2).

Dennis, I'm actually from NZ, doing a course in Australia - guess we stuck with the Canadian way too!

Thanks!
 
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