Stuck wiht logarithms

O

outime

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Joined
Apr 1, 2012
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6
-15=-12ln(5x)+7
-22=-12ln(5x)
-22/-12=ln(5x)
11/6=ln(5x)
e11/6 = e ln(5x)
e11/6 = 5x
x = e11/6 / 5

But I'm stock on that last step. Don't know what to do with the e11/6

Thanks in advance
 
outime said:
-15=-12ln(5x)+7
-22=-12ln(5x)
-22/-12=ln(5x)
11/6=ln(5x)
e11/6 = e ln(5x)
e11/6 = 5x
x = e11/6 / 5

But I'm stock on that last step. Don't know what to do with the e11/6

Thanks in advance
Click to expand...

Use your scientific calculator....
 
outime said:
-15=-12ln(5x)+7
-22=-12ln(5x)
-22/-12=ln(5x)
11/6=ln(5x)
e11/6 = e ln(5x)
e11/6 = 5x
x = e11/6 / 5

But I'm stock on that > > > last step. < < < Don't know what to do with the e11/6

Thanks in advance
Click to expand...
outime,

I would state that your "last step" is to check your candidate solution in
the original equation. For one of the considerations, if substituting it in
shows it taking the logarithm of zero or of a negative number, then you
would have to discard it. In that case, there would be no (real) solution.


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I have a TI-83 Plus and I think it works like yours, original poster.
Additionally,

hit "2nd" and then "LN."


That will produce this on the screen:

"e^("

Then type in "11/6." You should type in ")," but it may work without it.

After ending in either of those, press "Enter."
 
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