Stuck on polynomial

hubbylax

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Joined
Mar 26, 2006
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2
I solved all the other problems for homework except these:
Factor the following:

1) x^3+8
Tried (x+2) (x-2) (x-2) but that didn't work

and
2) 8x^3-125
Tried (2x-5) (2x+5) (2x-5) but that didn't work either!


Any ideas? Thanks for your help!
 
Hint 1: Sum-of-cubes formula.

Hint 2: Difference-of-cubes formula.

Eliz.
 
Great! thanks!

So that makes the answers:
1) (x+2) (x^2-2x+4)

and
2) (2x-5) (4x^2+10x+25)

I was trying to break it into three binomials.

Thanks again!
 
hubbylax said:
I solved all the other problems for homework except these:
Factor the following:

1) x^3+8
Tried (x+2) (x-2) (x-2) but that didn't work

and
2) 8x^3-125
Tried (2x-5) (2x+5) (2x-5) but that didn't work either!


Any ideas? Thanks for your help!

Here are two factoring patterns that you either need to memorize, or tattoo on your arm (and memorizing is cheaper and lots less painful!):

a<SUP>3</SUP> + b<SUP>3</SUP> = (a + b)(a<SUP>2</SUP> - ab + b<SUP>2</SUP>)

a<SUP>3</SUP> - b<SUP>3</SUP> = (a - b)(a<SUP>2</SUP> + ab + b<SUP>2</SUP>)

Your first problem is
x<SUP>3</SUP> + 8

Do you recognize that 8 is 2<SUP>3</SUP>?
So, you have
x<SUP>3</SUP> + (2)<SUP>3</SUP>
Use the first pattern to factor.

Your second problem is
8x<SUP>3</SUP> - 125

You can write 8x<SUP>3</SUP> as (2x)<SUP>3</SUP>
You can write 125 as (5)<SUP>3</SUP>

So, you have
(2x)<SUP>3</SUP> - (5)<SUP>3</SUP>
Use the second pattern.
 
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