Hey, I just have a quick question regarding a homework project my teacher gave my class. Solving two parts was easy and didn't require any cal, but I'm stuck on a spot.
The question was asked:
Suppose a skydiver leaps from a helicopter and falls in a straight line. He falls at a terminal velocity of 80 m/s for 19 seconds, at which time he opens his parachute. The velocity decreases linearly to 6 m/s over a two second period and then remains constant until he reaches the ground at t=40. The motion is described by the velocity function
80 if 0<(or equal to)t<19
v(t)= 783-37t if 19<(or equal to)t<21
6 if 21<(or equal to)t<(or equal to)40
Obviously I just multiply the top and the bottom by 19 to find the distance that is covered in that time, but I'm uncertain about the two seconds between them. Any and all help is appreciated, thanks!
The question was asked:
Suppose a skydiver leaps from a helicopter and falls in a straight line. He falls at a terminal velocity of 80 m/s for 19 seconds, at which time he opens his parachute. The velocity decreases linearly to 6 m/s over a two second period and then remains constant until he reaches the ground at t=40. The motion is described by the velocity function
80 if 0<(or equal to)t<19
v(t)= 783-37t if 19<(or equal to)t<21
6 if 21<(or equal to)t<(or equal to)40
Obviously I just multiply the top and the bottom by 19 to find the distance that is covered in that time, but I'm uncertain about the two seconds between them. Any and all help is appreciated, thanks!
