Stuck for 4 days please help me

[Gellie]

Given that the equations are true for all the value of x. Find A,B and C. Show your equations

6x^3-13x+9x+1= (Ax-B) (2x+1)(x-1) +C

 

[Deleted member 4993]

Given that the equations are true for all the value of x. Find A,B and C. Show your equations

6x^3-13x+9x+1= (Ax-B) (2x+1)(x-1) +C

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Please share your work/thoughts about this assignment. Since you have been working on it - you can at least "start" the problem. Tell us (show us) exactly where you are stuck. Otherwise we have to start with "definitions".

 

[Gellie]

 

[topsquark]

Given that the equations are true for all the value of x. Find A,B and C. Show your equations

6x^3-13x+9x+1= (Ax-B) (2x+1)(x-1) +C

Is there a typo? I would have expected 6x^3 - 13 x^2 + 9x + 1

-Dan

 

[Gellie]

Hi Dan,
There’s no typo.. The last two questions have been torturing me the past 4 days ?
Thank you so much ?
Regards,
Gellie

Is there a typo? I would have expected 6x^3 - 13 x^2 + 9x + 1

-Dan

 

[Deleted member 4993]

Hi Dan,
There’s no typo.. The last two questions have been torturing me the past 4 days ?
Thank you so much ?
Regards,
Gellie

View attachment 14336

Since you have done the first one - the last two are not very different from the first one!

Where exactly are you stuck!!

 

[Gellie]

I’m getting 2 values for B and C. Unlike the first number where there is a definite answer for A,B and C. I don’t know what I’m doing wrong.

Since you have done the first one - the last two are not very different from the first one!

Where exactly are you stuck!!

 

[Dr.Peterson]

I am convinced that the second problem does have a typo, as they would not have given two terms in x; surely they intended 6x^3 - 13x^2 + 9x + 1 as has been said. But with or without that fix, both the second and third have no solutions; the resulting systems are inconsistent. That's just what you pointed out, that one equation yields one value for B, and another yields a different value. That doesn't mean there are two values that work; it means that there is no solution that works for all the equations, and therefore mp solution for the problem as a whole.

Textbooks and teachers have been known to have errors. Don't assume you are doing something wrong -- ask your teacher!

 

[Gellie]

Dear Dr. Peterson,

Thank you !!!!! I really appreciate your input ? I thought I was going crazy ?

regards,
Gellie

I am convinced that the second problem does have a typo, as they would not have given two terms in x; surely they intended 6x^3 - 13x^2 + 9x + 1 as has been said. But with or without that fix, both the second and third have no solutions; the resulting systems are inconsistent. That's just what you pointed out, that one equation yields one value for B, and another yields a different value. That doesn't mean there are two values that work; it means that there is no solution that works for all the equations, and therefore mp solution for the problem as a whole.

Textbooks and teachers have been known to have errors. Don't assume you are doing something wrong -- ask your teacher!