Ok, so I would appreciate if someone would check these for me and make sure I'm right, or explain why I'm wrong. I would ask the teacher, and will if I dont figure it out, but I'm not at school until Wednesday. So! Here we go:
The show me the graph of f(x) with the points shown being (3,9),(0,3), and (-3,0). And I have to sketch the graph given the following functions. So I made a table, and would like to check and make sure I did it right.
1) y=f((1/3)x) which means it would be a horizontal stretch by a factor of three.
f(x)...|.y=(1\3)f(x)
(3,9).|.(9,9)
(0,3).|.(0,3)
(-3,0)|.(-9,0)
2)y=f(3x), a horizontal stretch by a factor of 1\3
f(x)...|.y=f(3x)
(3,9).|.(1,9)
(0,3).|.(0,3)
(-3,0)|.(-1,0)
3)y=(1\3)f(x), a vertical stretch by a factor of 1/3
f(x)...|.y=f(3x)
(3,9).|.(3,3)
(0,3).|.(0,1)
(-3,0)|.(-3,0)
right?? Or do I have it backwards and totally wrong
**edited**
The show me the graph of f(x) with the points shown being (3,9),(0,3), and (-3,0). And I have to sketch the graph given the following functions. So I made a table, and would like to check and make sure I did it right.
1) y=f((1/3)x) which means it would be a horizontal stretch by a factor of three.
f(x)...|.y=(1\3)f(x)
(3,9).|.(9,9)
(0,3).|.(0,3)
(-3,0)|.(-9,0)
2)y=f(3x), a horizontal stretch by a factor of 1\3
f(x)...|.y=f(3x)
(3,9).|.(1,9)
(0,3).|.(0,3)
(-3,0)|.(-1,0)
3)y=(1\3)f(x), a vertical stretch by a factor of 1/3
f(x)...|.y=f(3x)
(3,9).|.(3,3)
(0,3).|.(0,1)
(-3,0)|.(-3,0)
right?? Or do I have it backwards and totally wrong
**edited**