stress on a beam - 2

logistic_guy

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Determine the internal normal force, shear force, and bending moment at point \(\displaystyle C\) in the beam.

beam2.png
 
Let \(\displaystyle N_{C}\) be the internal normal force, \(\displaystyle V_{C}\) be the internal shear force, and \(\displaystyle M_{C}\) be the internal bending moment.

Since there are no horizontal forces at the point \(\displaystyle C\), \(\displaystyle N_{C} = 0\).

💪🥺
 
The vertical forces are:

\(\displaystyle F_A + F_B - 3000 -1500 = 0\)

In the next post, we will try to figure out a way to find the force \(\displaystyle F_A\) or the force \(\displaystyle F_B\).
 
We will set the point \(\displaystyle B\) as a reference and we will calculate the torques around it.

\(\displaystyle 6F_A - (4.5)30000 - (2)15000 = 0\)

\(\displaystyle F_A = 27500 \ \text{N}\)
 
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