I assume you meant to write u=sqrt(x-1) , du = 1/2u . No, if u=sqrt(x-1) then du does not equal 1/2u. Sorry! du = (1/(2u))dx or dx = 2udu.
You can't integrate (x^2+1)/sqrt(x-1)!!! You can however integrate [(x^2+1)/sqrt(x-1)]dx. How can you substitute if you do not have each piece that needs to written in terms of u? Int[(x^2+1)/sqrt(x-1)]dx = int[((u+1)^2 + 1)/u]2udu
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