reachyourgoals
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- Joined
- Feb 19, 2009
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During the 90's about 63% of high school graduates enrolled in college. The pollsters hope to estimate the percentage of this year's seniors planning to attend college with a margin of error no greater than 4%. What size sample would suffice if they want to have 90% confidence in the estimate?
Margin of error = z score ?(pq/n)
0.04= z score ?(0.63*0.37 /n)
90 percent confidence
Invnorm(.05)= -1.645
0.04= -1.645 ?(0.2331/n)
N= 394
Am i finding the z-score correctly?
Is the rest of my math correct?
Thsi is supposed to be an essay. Should i be checking for conditions? which ones?
Margin of error = z score ?(pq/n)
0.04= z score ?(0.63*0.37 /n)
90 percent confidence
Invnorm(.05)= -1.645
0.04= -1.645 ?(0.2331/n)
N= 394
Am i finding the z-score correctly?
Is the rest of my math correct?
Thsi is supposed to be an essay. Should i be checking for conditions? which ones?