Louise Johnson
Junior Member
- Joined
- Jan 21, 2007
- Messages
- 103
Question:
The volume of iced tea in cans are normally distributed with a mean of 250ml and a standard deviation of 4ml.Determine the range,to the nearest mL, of the volumes of the central 88% of the cans.
my answer:
invNorm .94 high Z score 1.554773593
invNorm .06 low Z score -1.554773593
\(\displaystyle \L\\\begin{array}{l}
\frac{{x - 250}}{4} = 1.554773593 = Xhigh256 \\
\frac{{x - 250}}{4} = - 1.554773593 = Xlow244 \\
\end{array}\)
This style of question I have no practice and am really unsure if I have gone about solving it in the correct way.
Thank you for your help
Louise
The volume of iced tea in cans are normally distributed with a mean of 250ml and a standard deviation of 4ml.Determine the range,to the nearest mL, of the volumes of the central 88% of the cans.
my answer:
invNorm .94 high Z score 1.554773593
invNorm .06 low Z score -1.554773593
\(\displaystyle \L\\\begin{array}{l}
\frac{{x - 250}}{4} = 1.554773593 = Xhigh256 \\
\frac{{x - 250}}{4} = - 1.554773593 = Xlow244 \\
\end{array}\)
This style of question I have no practice and am really unsure if I have gone about solving it in the correct way.
Thank you for your help
Louise