Standard Form of Parabola: y^2 - 4x - 6y + 9 = 0

[nigel]

Put y^2 - 4x - 6y + 9 = 0 into standard form.

Is the answer as follows?

x = (1/4)(y - 3)^2

please just tell me if the answer is correct, or if not what is the correct answer

Thank You

 

[stapel]

How does your book define "standard form"? (There is no fixed meaning to this term, is why I ask.)

Thank you.

Eliz.

 

[Mrspi]

Put y^2 - 4x - 6y + 9 = 0 into standard form.

Is the answer as follows?

x = (1/4)(y - 3)^2

please just tell me if the answer is correct, or if not what is the correct answer

Thank You

IF your book defines standard form for a parabola with vertex (h, k) and horizontal axis of symmetry as

x - h = a(y - k)<SUP>2</SUP>

THEN your answer is correct.