squaring a number and a radical

fgrey

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Jul 5, 2009
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(2+radical 5X-1)squared. I don't know how to access the extended numbers keys on my computer so I'll have to explain what I encounter.
I don't understand the squaring steps to get to 4+4radical 5x-1 + 5x-1. I end up with 4 +2(radical 5x-1)(5x-1).
It should be 4+4radical5x-1 +5x-1. My problem is that I don't understand the steps to squaring a number + a radical. I can solve squaring a radical fine.
 
fgrey said:
(2+radical 5X-1)squared. I don't know how to access the extended numbers keys on my computer so I'll have to explain what I encounter.
I don't understand the squaring steps to get to 4+4radical 5x-1 + 5x-1. I end up with 4 +2(radical 5x-1)(5x-1).
It should be 4+4radical5x-1 +5x-1. My problem is that I don't understand the steps to squaring a number + a radical. I can solve squaring a radical fine.

Do you understand this? (a + b)[sup:1uxh0rx7]2[/sup:1uxh0rx7]

(a + b)(a + b)
a[sup:1uxh0rx7]2[/sup:1uxh0rx7] + 2ab + b[sup:1uxh0rx7]2[/sup:1uxh0rx7]

In your problem, a = 2, and b = sqrt(5x - 1)

Substitute those expressions for "a" and "b" in

a[sup:1uxh0rx7]2[/sup:1uxh0rx7] + 2ab + b[sup:1uxh0rx7]2[/sup:1uxh0rx7]

2[sup:1uxh0rx7]2[/sup:1uxh0rx7] + 2(2)(sqrt(5x - 1)) + [sqrt(5x - 1)][sup:1uxh0rx7]2[/sup:1uxh0rx7]

Now, you said you can "square a radical fine," so I assume you know that [sqrt[5x - 1)][sup:1uxh0rx7]2[/sup:1uxh0rx7] is 5x - 1

4 + 4 sqrt(5x - 1) + 5x - 1

Combine like terms to finish the simplification.
 
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