PLease read carefully
- R represents the remainder of the number left over from the approximation ---> this part means the fractional part of the square root right? WHY Number in this above line means the square root ? Thats because square root of a number is in the form of (X + R)^2 so the R part has to be in the square root so thats why number is the square root. Am i right?
- What is this "left over from the approximation" line means? But my intution tells me that if my no is 10.81 and i approximate 3 in the first stage of thinking then the remainder R or the left over from the approximation will be 10.81- 3^2=1.81 but at the same time i am saying to myself that cannot be because R has to be a part of square root.MAYBE I am thinking of the normal remainder that we are generally left with when something is complelety divisble.
They are saying that X+R is the actual square root of some given number N; X is the approximation, and R is the difference between that and the actual square root, which they call a remainder. We could say that [MATH]R = \sqrt{N} - X[/MATH].
Their English is horribly written; you're right that the only way to figure out what they mean is to pick the interpretation that makes sense. So, yes, "number" in that line refers to the square root, not to the given number I called N.
And, no, R is not 10.81- 3^2=1.81, but the difference between the exact square root (which you don't know) and your approximation. In your example, the exact square root is 3.2878564445547193020469184596699..., so R is the difference between that and 3, namely 0.28785644455471930204691845966992... . Part of the point of any explanation of the method is that you are always working toward a number that you will never be able to write out exactly, so they've given that a name, X+R.
2.Why we are truncating 3 or why they are saying this line "Our approximation will always be the correct square root of the number truncated (not rounded) to the number of digits in our approximation ". I know that if something is truncated it is equal to only the non fractional part of the number i.e no of digits in our approximation .That means if my square root is 106.25 then digits of approximation is 3 i.e 106
Am i right??
Why they are saying it will be the correct square root of the number . if my number is 10.89 then if i truncate 3.3 to 3 then it becomes the square root of 9 not 10.89 then it is not correct
Why approximation means only the integer part only thats because if i know a no suppose 147 then it square root in my first approxmitation for surely will be 12 as i know square of 12 is close to 147 thats why right?
Truncation, as I demonstrated previously, is not always truncation to a whole number, taking the "non-fractional" part. You can truncate 3.16 to the tenths place and get 3.1; in that case, "the number of digits in our approximation" is 2 (3, 1). I would have said, "to the current place", in this case the tenths.
The "correct square root of the number" is the square root that you don't know yet. And what they are saying here is not that the approximation IS the correct square root, but that it is the RESULT of truncating the correct square root. I already said that I would have added a comma, at the least, to make it easier to tell what they mean! The approximation 3 is equal to "the exact root, 3.3, truncated to a whole number".
Each approximation in the algorithm has one more digit than the previous approximation. The first is just the integer part of the root; the second is everything through the tenths place (which for this example is all there is); and so on.
Now, I just did a search to locate
the original page you are referring to; it would be really helpful if people told us their sources so we could see the context! It's from a site with pages written by students, which are generally not bad but are not by really experienced teachers. Here is the paragraph you are asking about, quoted completely:
The square root of a number, N, is the number, M, so that M2 = N. The square root algorithm is set up so that we take the square root of a number in the form of (X + R)2. The square root of this number is obviously (X + R). X represents the current approximation for the square root, and R represents the remainder of the number left over from the approximation. Our approximation will always be the correct square root of the number truncated (not rounded) to the number of digits in our approximation. If we expand our number (X + R)2 it will equal X2 + 2RX + R2. This gives us the basis for our derivation of the square root algorithm.
Note, first, that you omitted the first sentence, which tells us that the author did in fact name the number N. It would have been better if he had mentioned both M (the correct/exact root) and N (the given number) more throughout this for clarity, which would have taken care of some of your confusion.
Anyway, don't worry too much if you had trouble following this; it's definitely not the best example of English to learn from, though it can be understood with effort. (I've probably written something occasionally that was hard to follow, too.)