lim t -> 0 of this function:
[sqroot(t^2 + 1) - 1] / t^2
wjm11 said:lim t -> 0 of this function:
[sqroot(t^2 + 1) - 1] / t^2
Try multiplying by
[sqroot(t^2 + 1) + 1]/ [sqroot(t^2 + 1) + 1]
Is that enough to get you started?
I got t^2/t^2(sroot[t^2 + 1]+1)
pka said:Can someone please tell me where the idea of "putting in the limiting value" come from. Has our calculus education come to such a low point? Do calculus teachers actually teach this?
Ummm...When were calculators invented? Complicated limit problems existed (and were solved) long before that time.johnjones said:Seems like everyone does it these days, even textbooks. Plug the limit in, then stop writing lim x-> 0 b/c we are subbing into the equation. How would you solve it w/o plugging it in then, pka? I mean, any calculus question in general. Like say you don't have a calculator and you have to solve a complicated limit problem?