Find the volume of the torus formed by rotating the region bounded by x^2 + y^2 = 9 about x=3.
Now when I solve for y I got positive or negative sqrt(9-x^2).
I was also wondering if it would be easier to solve for x instead because then I just need 1 integral for the upper - lower. I'm just stumped.
Now when I solve for y I got positive or negative sqrt(9-x^2).
I was also wondering if it would be easier to solve for x instead because then I just need 1 integral for the upper - lower. I'm just stumped.