[SPLIT] Find 3 consec. integers so sum of 1st, 2nd is 3 less tha

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eskimoxo

New member
Joined
Sep 19, 2008
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11
srry one more question :p
i have a communications question:
Find three consecutive intergers so that the sum of the first and the second is 3 less than twice the third interger.

so.. (x + y + 3) = 2z
(2 + 3 + 3) = 2(4)
assuming that the three consecutive intergers are 2, 3 and 4
8 = 8
but how do i mathematically justify that that is the right answer?
 
Re: Polynomial equations

Pick ANY 3 consecutive integers; like:

77,78,79: 77 + 78 + 3 = 2 * 79

1256,1257,1258: 1256 + 1257 + 3 = 1258 * 2

By the way, the simplest way to represent 3 consecutive integers is: n, n+1, n+2
 
Re: Polynomial equations

i tried that but this is what i got:
(x) + (x+1) +3 = 2(x+2)
2x + 4 = 2x + 4
0 = 0
 
Re: [SPLIT] Find 3 consec. integers so sum of 1st, 2nd is 3 less

thanks for the help?~
 
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