Split - Application Problems with formulas

Gr8fu13

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Feb 13, 2011
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If that is correct, I also have one more question.

The equation gives the distance, D, in miles that a person can see to the horizon from a height, h, in feet.

Solve this equation for h.
I have square root of h=D/1.2
h=(d/1.2)^2

Then, Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer.

I have:
D=1.2*Square root of 14255
D=143.273 miles

I then have to explain my answer. The only explaination I came up with is "You can see Cheyenne because the number is greater than 89 miles in distance away." Do these sound like reasonable answers? I just want to double check. Thanks again for all your help, hopefuly I am on the right track!
 
Re: Application Problems with formulas such as w=Cr^-2

Gr8fu13 said:
If that is correct, I also have one more question.

The equation gives the distance, D, in miles that a person can see to the horizon from a height, h, in feet.

Solve this equation for h.
I have square root of h=D/1.2
h=(d/1.2)^2

Then, Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer.

I have:
D=1.2*Square root of 14255
D=143.273 miles

I then have to explain my answer. The only explaination I came up with is "You can see Cheyenne because the number is greater than 89 miles in distance away." Do these sound like reasonable answers? I just want to double check. Thanks again for all your help, hopefuly I am on the right track!

Start a new thread with new problem.

You have not posted the original equation.

Assuming that the first part is correct - rest of it looks good to me.
 
The equation gives the distance, D, in miles that a person can see to the horizon from a height, h, in feet.

Solve this equation for h.
I have square root of h=D/1.2
h=(d/1.2)^2

Then, Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer.

I have:
D=1.2*Square root of 14255
D=143.273 miles

I then have to explain my answer. The only explaination I came up with is "You can see Cheyenne because the number is greater than 89 miles in distance away." Do these sound like reasonable answers? I just want to double check. Thanks again for all your help, hopefuly I am on the right track!

TTo determine how far in miles we can see from a building of height h ft., we use d = sqrt[1.5h].
To determine the height of a building we can see from a distance d off shore, we use h = sqrt(r^2 + d^2) - r, r and d in feet.
 
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