[SPLIT] 25 coins, quarters & nickels, sum to $2.85

MarqD19

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Oct 8, 2008
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Jeb has 25 coins. They are all quarters and nickels. He has a total of $2.85. How many quarters and nickels does he have? Construct an algebraic equation, solve for the variable, and answer the question. This problem must be solved using algebra! I realize that he has 11 quaters and 2 nickels. As for as constructing in algeraic terms and such , I'm lost please help!!! :?:
 
Re: price drop word problem

MarqD19 said:
... Jeb has 25 coins ... I realize that he has 11 quaters and 2 nickels ...

Hello Marq:

In the future, please click the [New Topic] button to post a new question. You're interrupting somebody else's conversation here.

You know that 11 + 2 does not equal 25, so you should realize that your answer is not correct.

Using algebra requires you to pick symbols to represent the unknowns.

Q = the number of quarters

N = the number of nickels

Q + N = 25

Now we have a choice. We can set up an equation to find the number of quarters, OR we can set up an equation to find the number of nickels.

It matters not which we choose, because we can always find the number of the other coin by subtracting from 25.

If you choose to find the number of quarters first, then solve the equation above for N to find an expression for the number of nickels that uses the symbol Q instead.

N = 25 - Q

Can you think of an equation that you can write involving the value of the nickels and the value of the quarters and the total worth of all the coins? Use the symbol Q to represent the number of quarters, and use the expression 25-Q to represent the number of nickels.

Solve this equation for Q to find the number of quarters. Once you know the number of quarters, the number of nickels is 25-Q.

If you need more help, then please show whatever work you've been able to do and try to say something about why you're stuck.

Cheers,

~ Mark :)
 
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