somebody help me??????

mathhelp1a

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Oct 4, 2009
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4 x^2 + 4 y^2 -2x + 8y -4 = 400

find derivative and simplify
is the answer

y' = 2-8x / 8y + 8
 
mathhelp1a said:
4 x^2 + 4 y^2 -2x + 8y -4 = 400

find derivative and simplify
is the answer

y' = 2-8x / 8y + 8

How did you get that - please show your work.
 
mathhelp1a said:
4 x^2 + 4 y^2 -2x + 8y -4 = 400

find derivative and simplify
is the answer

y' = 2-8x / 8y + 8

I would attempt this question as following:
4y^2 +8y = 4x^2 -2x +404
dy/dx (4y^2) + dy/dx (8y) = 8x-x
dy/dx * (4y^2+8y) = 7x
dy/dx = 7x / (4y^2+8y)
 
mathhelp1a said:
4 x^2 + 4 y^2 -2x + 8y -4 = 400

find derivative and simplify
is the answer

y' = 2-8x / 8y + 8

4 x^2 + 4 y^2 -2x + 8y -4 = 400

8x + 8y*y' - 2 + 8y' = 0

8y'(y+1) = 2(1-4x)

y' = (1-4x)/[4(y+1)]
 
mathhelp1a said:
Stop posting!!!!!!!!!!! it's a simply question. Just google how to derivative single variable or read your text book!
And about how to simplify that equation, it's very simple, that equation just equals to y' = (1-4x)/(4y+4). I don't understand what the **** you want. This question is very simple. Maybe you should consider going to lecutres or reading the dam book! Move on!
 
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