In order to do this problem you need to use either the quadratic formula or factor. Personally, I prefer to factor, as I find it to be less time consuming. Not all quadratic formulas can be factored, though this one can.
Here is an example of how to factor a quadratic equation, hopefully you can follow along. =)
y = x[sup:yeovbmia]2[/sup:yeovbmia] - 8x + 16
The coefficient in front of x[sup:yeovbmia]2[/sup:yeovbmia] is one. I then multiply that by c, which is 16 in this situation. 1 x 16 = 16.
I then need to find two numbers that are divisible by 16 that equal b, which is -8 in this situation, when they are added together.
-4 + -4 = -8
-4 x -4 = 16
So then I am going to use a box, which I'm not sure if you have ever used before, but I find this much simpiler than foiling.. especially when you are going backwards.
______ ______
_____ x[sup:yeovbmia]2[/sup:yeovbmia] -4x
_____ -4x 16
I then want to see what is common to fill out the spaces above the box.
x -4
x x -4x
-4 -4x 16
This equation factors out to (x-4)[sup:yeovbmia]2[/sup:yeovbmia].
When I set x - 4 to equal zero, I discover that the solution is 4. There is only one solution to this problem because the factor has a multiplicity.
I'm not sure how understandable this will be, as it's easier for me to show someone how to do an equation in person, but hopefully you will get some use out of this. Let me know if there is anything that needs to reexplained.