solving x from log eqn: (1 / 5 - log x) + (2 / 1 + log x) =1

grapz

Junior Member
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Jan 13, 2007
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(1 / 5 - log x ) + ( 2 / 1 + log x ) = 1

Solve for x

This is what i did: I made the denominators the same for both fractions. After that i am not sure what to do
 
\(\displaystyle \L \frac{1}{ 5\, -\, log x}\, +\, \frac{ 2}{ 1\, +\, log x }\, =\, 1\)

\(\displaystyle \L \frac{\(1\,+\,logx\) \,+\, 2\(5\,-l\,og(x)\)}{ (5\,-\,log x)(1\, +\, log x)}\, =\, 1\) (combine)

\(\displaystyle \L \(1\,+\,logx\)\, +\, 2\(5\,-\,log(x)\)\, =\, (5\,-\,log x)(1\, +\, log x)\) (multiply both sides by the denominator)

\(\displaystyle \L 11\, -\, log(x)\, =\, (5\,-\,log x)(1\, +\, log x)\) (simplify)

Now multiply out and move everything to one side and solve the resulting quadratic equation.
 
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