solving |x + (3/5)| = |x - 2|

[Dano1284]

|x + 3/5| = |x - 2|

That's three over five, incase there's any confusion.

Can some one please solve this out, and explain the solution.

I can't seem to get this one done.

 

[stapel]

How far have you gotten? Where are you stuck? For instance, you've found the x-values that determine the sign inside each absolute value, right? And then used this to divide the number line into cases: x < -3/5, -3/5 < x < 2, etc. And... then what?

Please be specific. Thank you.

Eliz.