Solving square root equation: 3 sqrt x2 = 9

[cakers44]

I need to solve the following:

3√x2 = 9

OK that three in front of the square root symbol is supposed to be in superscript - don't know how to show that here. But is that then to be be added to the "2", so that instead of x squared, it is x to the fifth power?

 

[royhaas]

If it looks like \(\displaystyle ^3\sqrt{x^2}=9\), then it is the cube root of \(\displaystyle x^2\) which is the same as \(\displaystyle x^{2/3}\) power.

 

[cakers44]

Yes that's what it looks like.

So is the anser
x=6?

 

[stapel]

...that three in front of the square root symbol is supposed to be in superscript - don't know how to show that here.

Did the instructor not cover terminology in class? Have you not heard of "cube" roots and "radical" signs...? (It sounds like you mean "the cube root of" but have never heard that terminology, is why I ask.)

But is that then to be be added to the "2", so that instead of x squared, it is x to the fifth power?

Is the "2" meant to be a power? If so, is it on the "x", on the entire radical, or something else? Has your class covered exponents or roots at all?

Thank you.

Eliz.

 

[tkhunny]

No. You are guessing.

Show your work. How did you get that? That's an EXPONENT, not a multiplication.