solving log eqns algebraically: ln(x + 1) - ln(x - 2) = ln x

kryms3n

New member
Joined
Dec 4, 2006
Messages
14
In these exercises solve the logarithmic equation algebraically. Roung the result to three decimal places

96. ln(x + 1) - ln(x - 2) = ln x^2

98. log 4x - log (12 + radical x) = 2

the first part of the equations w/ the log have a base of 10
 
Re: another log problem

kryms3n said:
96. ln(x + 1) - ln(x - 2) = ln x^2
Are these quizzes? We don't have time or effort for games, really, except for a few that appear in the game zone.

SIMPLE Log Rules

ln(x + 1) - ln(x - 2) = ln x^2

ln((x+1)/(x-2)) = ln(x^2)

(x+1)/(x-2) = x^2

Now what?
 
no

no
it is part of my homeowrk
that i dont understand

i got that far
and have no idea how to go farther
you could make it into a cubic functin
but then i am stuck
 
Wait

wait
u have to divide
for the log process

because both of the logs are subtracted
 
Re: no

kryms3n said:
i got that far
See, that is useful information. Why didn't you tell us that in the first place? Why didn't you show ANY work?

and have no idea how to go farther
I NEVER believe that.

you could make it into a cubic functin
See, you are proving me right. You DO have a clue. What's stopping you from proceeding as you have suggested?
 
okay

okay
thank you
and sorry for the hassle

um
i was just wondering
how do i show my work
and make it look 'professional'
with it coming out of like paint
instead of just writingit in here

thank you
and il do better next time
 
Re: okay

kryms3n said:
how do i show my work
and make it look 'professional'
First, practice. Try to enter what you want and we'll give you pointes on improvement.

Second, learn a little LaTeX. The "Forum Help" drop-down has several useful selections. You can download programs to code the LaTeX for you, but I just code it directly.
 
Top