Solving Limits Problem

april19

New member
Joined
Sep 22, 2010
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27
I need to solve x in the following function so as x is approaching 3.
I think my problem right now is more a trig. problem because I can't solve it.

f(x)=5-2sin(x-3) When x=3, f(x)=5

What is x when f(x)=5.5 and f(x)=4.5?

Here's what I got so far.

5-2sin(x-3)= 5.5
2sin(x-3)=0.5
sin(x-3)=0.25

I cheated and saw the answer has arcsin in it. I can't remember how to solve this.
Any help from anybody?
Thanks.
 
Apply arcsin\displaystyle arcsin to both sides of your last equation.
 
f(x) = 52sin(x3).\displaystyle f(x) \ = \ 5-2sin(x-3).

limx3f(x) = 52sin(33) = 52sin(0) = 52(0) = 5.\displaystyle \lim_{x\to3}f(x) \ = \ 5-2sin(3-3) \ = \ 5-2sin(0) \ = \ 5-2(0) \ = \ 5.

f(x) = 5.5 = 52sin(x3), solve for x.\displaystyle f(x) \ = \ 5.5 \ = \ 5-2sin(x-3), \ solve \ for \ x.

2sin(x3) = .5\displaystyle -2sin(x-3) \ = \ .5

sin(x3) = 14\displaystyle sin(x-3) \ = \ \frac{-1}{4}

(x3) = arcsin(1/4) =˙ .25268\displaystyle (x-3) \ = \ arcsin(-1/4) \ \dot= \ -.25268

Hence, x =˙ 2.74732\displaystyle Hence, \ x \ \dot= \ 2.74732

Now, you should be able to do the next one.\displaystyle Now, \ you \ should \ be \ able \ to \ do \ the \ next \ one.
 
Great! Thanks!!!
Wrecked my brain on this one. Can't believe it was that simple to solve it.
 
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