Solving Inequalities

[Sundelights]

I do not need the answer but could someone please help me start this problem. I think I'm overthinking it, but whatever I try, it's just not working out.

-2/5x - 9 < 9/10

Do I multiply each side by the reciprocal or subtract first? I would appreciate any help. Thank you so much!

 

[Deleted member 4993]

I do not need the answer but could someone please help me start this problem. I think I'm overthinking it, but whatever I try, it's just not working out.

-2/5x - 9 < 9/10

Do I multiply each side by the reciprocal or subtract first? I would appreciate any help. Thank you so much!

-2/5x - 9 < 9/10


-2/5x < 9/10 + 9

Now continue by further isolating 'x'.

 

[Sundelights]

-2/5x - 9 < 9/10


-2/5x < 9/10 + 9

Now continue by further isolating 'x'.

so addition then multiply by the reciprocal?

 

[lookagain]

-2/5x - 9 < 9/10

Sundelights,

what is your exercise supposed to be?


Is it supposed to be \(\displaystyle \ \frac{-2}{5}x - 9 \ < \ \frac{9}{10} \ \ or \)

\(\displaystyle \frac{-2}{5x} - 9 \ < \ \frac{9}{10} \ ?\)


If it is the latter, then you would type along this form:


-2/(5x) - 9 < 9/10