Solving Formulas Need urgent help!!

[speed4baseball]

ok so this is the problem:

y=v*it + 1/2gt^2 (solve for v*i) *=means that the is in a foot note like way aka v__ i <-- would go in that place but lower instead of exponent its under the line

^ if not then solve this one
P=i^2R solve for i
please i just need someone.s help and i.ve erased my work for both problems over 5 times!! thank you anyone who can help me

 

[mmm4444bot]

*=means that the is in a foot note like way aka v__ i This is English? :roll:

I'll use asterisks as multiplication signs. I'll type "v sub i" as v_i.

y = v_i * t + 1/2 * g * t^2

Subtract 1/2 * g * t^2 from both sides, in order to first isolate v_i * t.

Then, divide both sides by t, in order to isolate v_i.

You're done.

------------------------------------------

P = i^2 * R

Divide both sides by R, in order to first isolate i^2.

Then, take the square root of both sides, in order to isolate i.

Don't forget that the square root of i^2 is |i|, so there is both a positive and negative root of i^2.

 

[speed4baseball]

for the first problem what is the final answer?

 

[Deleted member 4993]

for the first problem what is the final answer?

Why don't you work through and tell us what you found. If you made a mistake - we'll correct it.

 

[speed4baseball]

Mr/Ms Khan.
*nice quote by the way

i subtracted 1/2gt^2 like i was suggested and worked on from there
divided 1/2gt^2 by vt to isolate v_i
and my answer was v_i = 1/2gt^2 divided by t

 

[mmm4444bot]

my answer was v_i = 1/2gt^2 divided by t The right-hand side simplifies.

 

[Deleted member 4993]

ok so this is the problem:

y=v*it + 1/2gt^2 (solve for v*i) *=means that the is in a foot note like way aka v__ i <-- would go in that place but lower instead of exponent its under the line

^ if not then solve this one
P=i^2R solve for i
please i just need someone.s help and i.ve erased my work for both problems over 5 times!! thank you anyone who can help me

\(\displaystyle y \ = \ v_i\cdot t \ + \ \frac{1}{2}\cdot g\cdot t^2\)

\(\displaystyle v_i\cdot t \ = \ y \ - \ \frac{1}{2}\cdot g\cdot t^2\)

\(\displaystyle v_i \ = \ \frac{y}{t} \ - \ \frac{1}{2}\cdot g\cdot t\)