Solving for x with fractions in it

E

ElleanineChan

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Aug 28, 2010
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My problem is simply to solve for x. I know the answer, but I don't know how to get to it.

(1/2) x - 4 = (3/4)x

Apparently, x = -16. I don't understand how.
The part of the problem I'm having trouble with is getting the fractions into a workable state. I'm really bad with fractions. If I could figure out how to get the fractions out of the way, I'm sure I could probably finish solving it.
 


The greatest denominator in common with the fractions is 4.

If you start by multiplying both sides of the equation by 4, all of the fractions will cancel.

 
Do you mean times it by 4 over 1, or times it as 4 over 4 or what? And how would it cancel, would it just take out the denominators in both or take out the entire fraction?
 


I said multiply by 4.

That means multiply by 4.

4/1 = 4, so, yes, you can multiply by 4/1.

4/4 = 1, so, no, do not multiply by 1.

If we multiply 4 times 1/2, the denominator 2 cancels.

Do you need to first review lessons on how to do arithmetic with fractions?

Here's a beginner's site on how to do arithmetic with fractions.

 
Oh, I see now. Thank you! I understand how to get to the answer now. I was just a little confused, and started to overthink it in silly ways. Thank you for the site as well.
 


I see them both the same.

When I look at Denis' version, I see the coefficient 1/2 in front of x and the coefficient 3/4 in front of x.

When I look at Elleanine's version, I see x over 2 and 3x over 4.

It's the visual analog of ambilevousness (sorry Webster). :D

 
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