Please show us what you have tried and exactly where you are stuck.Anyone know how to solve for 2cos(x)-1=-1.2814 while in the 2nd quadrant?
If you are allowed to - use a calculator to calculate 'x'.Well, I added one to both sides (2cos(x)= -0.2814) , divided both sides by two (cos(x)= -0.2814/2), then I found the inverse cos of both sides (x= (cos^-1)(-0.2814/2).
When I do that, which is the right thing to do, I get 98.088354 degrees. I can't see how you would get 11.74.Well, I added one to both sides (2cos(x)= -0.2814) , divided both sides by two (cos(x)= -0.2814/2), then I found the inverse cos of both sides (x= (cos^-1)(-0.2814/2).
You were asked how you got 11.74! "cos^(-1)(-0.2814)" is NOT 11.74 whether you are in "degrees", "radians", or "grads".Well, I added one to both sides (2cos(x)= -0.2814) , divided both sides by two (cos(x)= -0.2814/2), then I found the inverse cos of both sides (x= (cos^-1)(-0.2814/2).